Prove that a connected graph G is a tree if and only if every edge of G is a bridge.
Therefore: $$ \sum_i=1^n deg(v_i) = 2 \times |E| $$
Remove one pendant vertex and its incident edge. The remaining graph is still a tree (it remains connected and circuit-less) with By our assumption, this smaller tree has Adding back the pendant vertex and its edge gives , the number of edges is Commonly Requested Topics for Solutions
Most solutions for Deo’s exercises are static PDFs. They give the final answer but don’t explain how to derive the proof or why a certain condition fails. Deo’s problems often ask: